Answer:
all work is shown and pictured
Here are the scores of 17 students on a history test. 62, 65, 66, 67, 67, 76, 77, 78, 79, 80, 86, 88, 88, 89, 90, 91, 92 Notice
creativ13 [48]
I added a picture with it for you. I suggest that before this becomes an issue you take some time and study box and whisker plots, because they tend to show up on a lot of standardized math tests.
Answer:
The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.7291
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have
. So



The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Answer:
Option A is correct.
Step-by-step explanation:
The height of the rectangular pack is h1 = 4r
The height of the parallelogram = 2r + the height of equilateral triangles with a side of 2r
The height of equilateral triangle with a side of 2r = (side)/2*√3
=(2r)/2 *√3 = r√3
The height of the parallelogram h2 = 2r+r√3 = r(2+√3)
So,the ratio of h1 to h2 is :
4r : r(2 +√3)
Cancelling r we get
Hence, the ratio is 4 : 2 +√3
You marked the right answer. It is true. XD