R is between S and T, so this implies that R is on line ST and we can say
SR+RT = ST
plug in the given expressions to get
(-2x+24)+(4x+10) = 4x+12
Now solve for x
(-2x+24)+(4x+10) = 4x+12
-2x+24+4x+10 = 4x+12
2x+34 = 4x+12
2x+34-2x = 4x+12-2x
34 = 2x+12
34-12 = 2x+12-12
22 = 2x
2x = 22
2x/2 = 22/2
x = 11
If x = 11, then RS is,
RS = -2*x+24
RS = -2*11+24
RS = -22+24
RS = 2
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Answers:
x = 11 and RS = 2
Answer:
Step-by-step explanation:
t + u = 11 ----------- (1 )
10t + u = 10u + t - 9
10t + u - 10u - t = -9
10t - t + u - 10u = - 9
Combine like terms
9t - 9u = -9
Divide the entire equation by 9

t - u = -1 --------------(2)
Add equation (1) & (2) and so, u will be eliminated and we can find the value of t
(1) t + u = 11
(2) <u>t - u = -1</u>
2t = 10
t = 10/2
t = 5
Plugin t = 5 in equation (1)
5 + u = 11
u = 11 - 5
u = 6
The original number is 56