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Maslowich
3 years ago
12

I need helps can someone help me please!!!

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

JK=27

LM=27

KL=16

MJ=16

Step-by-step explanation:

JK=4x+7

=27

LM=5x+2

=27

KL=2y-2

=16

MJ=y+7

=16

so, JK= 27 and KL=16

(I hope u got it)

notsponge [240]3 years ago
4 0

Answer:

Jk= 27

LM= 22

KL= 16

MJ=16

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M
Olegator [25]

Answer:

the answer is B

Step-by-step explanation:

4 0
3 years ago
If the start time is 8:34 amd the elapsed timne is 3 hours and 18 minutes what is the end time
mr_godi [17]
Forget the '34' part of 8:34 and the '18' minutes from 3 hours and 18 minutes for now.

Just add 3 hours on to 8, to get 11. Then, bring back the 34 and 18 and add them together. 34 + 12 = 52. Now put that 52 on the end of the 11, and you get 11:52 as the end time. 
3 0
3 years ago
Read 2 more answers
B: Alex is 12 years older than George.
UkoKoshka [18]

Answer:

The ratio of George age to Carl's age is 1:12.

Step-by-step explanation:

Let the age of George be 'g'.

Let the age of Alex be 'a'.

Also Let the age of Carl be 'c'.

Given:

The sum of their ages is 68.

So equation can be framed as;

g+a+c=68 \ \ \ \ equation 1

Also Given:

Alex is 12 years older than George.

So equation can be framed as;

a =g+12 \ \ \ \ equation \ 2

Now Given:

Carl is three times older than Alex.

c=3a

But a =g+12

So we get;

c = 3(g+12) \\\\c= 3g+36 \ \ \ \ equation \ 3

Now Substituting equation 2 and equation 3 in equation 1 we get;

g+a+c=68\\\\g+g+12+3g+36=68\\\\5g+48=68

Subtracting both side by 48 using subtraction property of equality we get;

5g+48-48=68-48\\\\5g=20

Now Dividing both side by 5 using Division property of equality we get;

\frac{5g}{5}=\frac{20}{5}\\\\g =4

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Also Carl's age c=3g+36=3\times 4+36 =12+36 =48\ years

Now we need to find the ratio of George age to Carl's age.

\frac{g}{c}=\frac{4}{48} = \frac{1}{12}

Hence  the ratio of George age to Carl's age is 1:12.

3 0
3 years ago
What must be the value of x so that lines a and b are parallel lines cut by transversal f?
ExtremeBDS [4]

we know that

if the lines a and b are parallel lines cut by transversal f

then

(6x-36)=96 --------> by alternate exterior angles

solve for x

(6x-36)=96\\ 6x=96+36\\6x=132\\x=(132/6)\\x=22\ degrees

therefore

<u>the answer is</u>

the value of x is 22\ degrees

5 0
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Vitek1552 [10]

Answer:

Solution,\\Area~of~triangle=\frac{1}{2} (base)(height) = \frac{1}{2}(2x+\frac{1}{4}) (x-8)\\~~~~~~~~~~~~~~~~~~~~~~~~ =\frac{1}{2}[2x^2-16x+\frac{1}{4}x-\frac{1}{4}(8)]\\ ~~~~~~~~~~~~~~~~~~~~~~~~ =\frac{1}{2}[2x^2-\frac{63}{4}x - 2]\\~~~~~~~~~~~~~~~~~~~~~~~~=x^2-\frac{63}{8}x-1

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