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chubhunter [2.5K]
4 years ago
12

A normal distribution has mean μ and standard deviation σ .An x-value is randomly selected from the distribution. Find P(μ−σ≤x≤μ

+ 3σ)
P(μ−σ≤x≤μ+ 3σ)=
Mathematics
1 answer:
dlinn [17]4 years ago
5 0

Answer:

The probability that a randomly selected  x-value lies between μ − 2σ and μ is the  shaded area under the normal curve shown.  P(μ − 2σ ≤ x ≤ μ) = 0.135 + 0.34 = 0.475

Step-by-step explanation:

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