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lukranit [14]
3 years ago
5

I need help on this can someone help me

Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:

<em>Answer is </em><em>63</em>

<em>Answer</em><em> </em><em>is</em><em> </em><em>rounded</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>nearest</em><em> </em><em>tenth</em><em> </em><em>place</em><em>. </em>

Step-by-step explanation:

area \: of \: sector \:  =  \frac{theta}{360}  \times \pi \:  {r}^{2}  \\ here \: theta \:  = 72 \: degrees \: and \\ radius \:  = 10 \\ on \: substituting \: the \: values \: in \: the \: formula \\ area \: of \: sector \ =  \frac{72}{360}  \times \pi \:  {10}^{2}  \\   \:  \:  = \frac{1}{5}  \times 100\pi \\  = 0.2 \times 100 \times \pi \\  = 62.83 \\ are \: of \: sector \: is \: approximately \:  \\ equal \: to \: 63

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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= 2 - 4
jekas [21]

Answer:

Please find attached the required inverse of a function chart

Step-by-step explanation:

The inverse of a function is found by reversing the operations of the  function

The inverse of the function f(x) = 2·x - 4 is found as follows;

x = 2·x - 4

x + 4 = 2·x

x = (x + 4)/2 = x/2 + 2

Therefore, the inverse of the function f(x) = 2·x - 4 is f(x) = x/2 + 2

The inverse function is plotted by generating data points as follows;

{}x         {}          f(x)

0                2

1                  2.5

2                 3

3                  3.5

4                   4

5                   4.5

6                   5

7                   5.5

8                   6

9                   6.5

10                  7

11 {}                   7.5

12{}                    8

13                 8.5

14                  9

15                  9.5

16               10

5 0
3 years ago
A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556
MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

6 0
3 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
2 years ago
A subscription to an online video game costs $14.95 per month. The cost of playing practice matches is included in the
kifflom [539]

Answer:

she participated in 4 tournaments

4 0
3 years ago
A geer on a machine turns at a rate of 3 revolutions per second. Identify the key feauters of the graph of this function
Harman [31]

https://rosemont.scusd.edu/sites/main/files/file-attachments/010516_answers_to_last_nights_hw.pdf

8 0
3 years ago
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