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3 years ago

I need help on this can someone help me

Mathematics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

Answer is 63

Answer is rounded to the nearest tenth place.

Step-by-step explanation:

$area \: of \: sector \: = \frac{theta}{360} \times \pi \: {r}^{2} \\ here \: theta \: = 72 \: degrees \: and \\ radius \: = 10 \\ on \: substituting \: the \: values \: in \: the \: formula \\ area \: of \: sector \ = \frac{72}{360} \times \pi \: {10}^{2} \\ \: \: = \frac{1}{5} \times 100\pi \\ = 0.2 \times 100 \times \pi \\ = 62.83 \\ are \: of \: sector \: is \: approximately \: \\ equal \: to \: 63$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

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A_____ function is a function that can be expressed as the quotient of two polynomial functions in wich the denominator does not

Korolek [52]

Answer:

rational

Step-by-step explanation:

that is literally the definition of a rational number, just change the part where it says function to number and polynomial functions to number as well.

4 0

3 years ago

A line passes through the points (1, 3) and (3, -1) on a coordinate plane. What is the equation of this line in slope-intercept

FromTheMoon [43]

Answer:

y=[-2]x[+][5]

Step-by-step explanation:

$\frac{-1-3}{3-1}=\frac{-4}{2} =-2$ m= -2

Using the point (1,3) Find the value of b

3= -2(1)+b

3= -2+b

+2 +2

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5=b

y= -2x+5

4 0

2 years ago

Read 2 more answers

Can I get help with this? Thanks! :)

ycow [4]

Answer:

The answer is 17

Step-by-step explanation:

8^2+15^2=c^2

64+225=c^2

289=c^2

Square root both sides

c=17

8 0

3 years ago

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 . a.

Anastasy [175]

Answer:

a) 0.073044

b) 0.75033

c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

Step-by-step explanation:

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 .

a. Find the probability that an individual distance is greater than 218.00 cm.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 218

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

For x > 218

z = 218 - 205.5/8.6

z = 1.45349

Probability value from Z-Table:

P(x<218) = 0.92696

P(x>218) = 1 - P(x<218) = 0.073044

b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00

When = random number of samples is given, we solve using this z score formula

z = (x-μ)/σ/√n

where

x is the raw score = 204

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

n = 15

For x > 204

Hence

z = 204 - 205.5/8.6/√15

z = -0.67552

Probability value from Z-Table:

P(x<204) = 0.24967

P(x>204) = 1 - P(x<204) = 0.75033

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

3 0

3 years ago

A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a

natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, . . . , x₂₃ be the actual data observed by the student

The sample means = x₁ + x₂ + . . . , x₂₃ / 23

$= \frac{x_1 +x_2 +...x_2_3}{23}$

= 2.3hr

⇒ $\sum xi =2.3 \times 23 = 52.9hrs$

let x₁ , x₂, . . . , x₂₃ arranged in ascending order

Then x₂₃ was 10 and has been changed to 14

i.e x₂₃ increase to 4

Sample mean $= \frac{x_1 +x_2 +...x_2_3}{23}$

$\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47$

therefore, the new sample mean is 2.47

2) For the old data set

the median is $x_1_2(th)$ values

$[\frac{n +1}{2} ]^t^h value$

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = $[{x_1_2]^t^h value$ remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

$=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)$

The new sample standard sample deviation is calculated as

$= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)$

Now, when we compare (1) and (2) the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)² ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0

3 years ago