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2 years ago

I need help on this can someone help me

Mathematics

1 answer:

Artist 52 [7]2 years ago

6 0

Answer:

Answer is 63

Answer is rounded to the nearest tenth place.

Step-by-step explanation:

$area \: of \: sector \: = \frac{theta}{360} \times \pi \: {r}^{2} \\ here \: theta \: = 72 \: degrees \: and \\ radius \: = 10 \\ on \: substituting \: the \: values \: in \: the \: formula \\ area \: of \: sector \ = \frac{72}{360} \times \pi \: {10}^{2} \\ \: \: = \frac{1}{5} \times 100\pi \\ = 0.2 \times 100 \times \pi \\ = 62.83 \\ are \: of \: sector \: is \: approximately \: \\ equal \: to \: 63$

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Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work.

But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

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Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

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