7. A clothing trunk measures 2.5 feet wide by 1.5 feet

Brian bought a 15 pound bag of comcrete. he split the bag into smaller bags that each hold two and a half pounds. how many small

Westkost [7]

Okay. You have 15 lbs of concrete, and x bags that can individually hold 2.5 lbs. What you need to do is divide 15 by 2.5, and the quotient will be 6.
Problem: 15 ÷ 2.5 = 6
So the answer to your problem will be: 6 bags.

3 0

3 years ago

Read 2 more answers

Please help quickly! Will give points to 1st right answer!

Ksenya-84 [330]

Answer:

g(x) = log( x + 1 ) + 4

Step-by-step explanation:

f(x) is the parent equation so to get g(x) we shifted f(x) four units up and one unit to the left.

4 0

2 years ago

3х + 16 = 24<br> What is the answer??

Rama09 [41]

Answer:

x = 8/3

Step-by-step explanation:

3x + 16 = 24

3x = 24 - 16 (subtract 16 from both sides)

3x = 8

x = 8/3 (divide both sides by 3)

3 0

2 years ago

Consider Functions F and G

Zanzabum

Answer:

A

Step-by-step explanation:

We are given two functions:

$\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}$

And we want to find:

$f(x)+g(x)$

Thus:

$\displaystyle =\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}$

We can factor the denominator of the first term:

$\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}$

In order to add the two terms, we must have a common denominator. To achieve this, we can multiply to second term by (x - 4). Therefore:

$\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}\Big(\frac{x-4}{x-4}\Big)$

Multiply:

$\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{x-4}{(x+10)(x-4)}$

Combine:

$\displaystyle =\frac{(x-16)+(x-4)}{(x+10)(x-4)}$

Simplify:

$\displaystyle =\frac{2x-20}{(x+10)(x-4)}$

We can expand the denominator:

$\displaystyle =\frac{2x-20}{x^2+6x-40}$

Therefore, our answer is A.

6 0

2 years ago

Read 2 more answers

Research has suggested that musicians process music in the same cortical regions in which adolescents process algebra. When taki

svet-max [94.6K]

Answer:

c. an observed difference is 0.12 and P < 0.0001

Step-by-step explanation:

Let p1 be the proportion of the students who received musical instruction received a passing grade

Let p2 be the proportion of the students who didn't receive musical instruction received a passing grade

Null and Alternative hypotheses are:

$H_{0}$ : p1-p2=0

$H_{a}$ : p1-p2≠0

Test statistic can be found using the equation:

$z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of the students who received musical instruction received a passing grade ( $\frac{2818}{3239} =0.87$ )

p2 is the sample proportion of the students who didn't receive musical instruction received a passing grade ( $\frac{2091}{2787} =0.75$ )

p is the pool proportion of p1 and p2 ( $\frac{2818+2091}{6026}=0.81$ )

n1 is the sample size of the students who received musical instruction (3239)

n2 is the sample size of the students who didn't receive musical instruction (2787)

Thus, $z=\frac{0.87-0.75}{\sqrt{{0.81*0.19*(\frac{1}{3239} +\frac{1}{2787}) }}}$ ≈ 11.84 gives p-value < 0.0001

Observed difference is: 0.87-0.75=0.12

5 0

3 years ago