Rewrite in standard form and use this form to find the vertex
(h,k).(0,7)
then just graph the (0,7) the just down cross the line down like a triangle
Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
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You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Answer:
the bottom right
Step-by-step explanation:
Answer:
x=2+ or - the square root of 3
Step-by-step explanation:
solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
To determine the answer it would be helpful if we write this equation into the slope intercept form which is expressed as:
y = mx+b
<span> y−2x=816
y = 2x + 816
4x=2y
y = 2x
We can see that the slope of the two equations are the same. Therefore, they are parallel which means they do not intersect. The correct answer is the third option, there is no solution.</span>