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3 years ago

Subtract 4p^2-9p+11 from p^2-5p+4 Your answer should be a polynomial in standard form.

Mathematics

1 answer:

pishuonlain [190]3 years ago

3 0

Answer:

$p^2 - 5p + 4$

$4p^2 - 9p + 11$

-⠀⠀⠀+⠀⠀-

$-3p^2 + 4p -7$

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Answer:

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3 years ago

Please help with this question

aleksandr82 [10.1K]

Answer:

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Step-by-step explanation:

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3 years ago

NEED HELP PLZ HURRY

Vlada [557]

(-2,8) (1,2)
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6 0

3 years ago

Tell whether the given value is a solution of the inequality.<br><br> x − 2 ≥ −1.6 ; x = 0.8

Finger [1]

Answer:

No, it' snot a solution

Step-by-step explanation:

x − 2 ≥ −1.6

x - 2 + 2 ≥ -1.6 + 2

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7 0

3 years ago

how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?

VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Solution:</u></h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Therefore, we frame a equation as:</u></h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

$\frac{25}{100} \times x + \frac{50}{100} \times (40-x) = \frac{30}{100} \times 40\\\\0.25x + 0.5(40-x) = 12\\\\0.25x + 20 - 0.5x = 12\\\\0.25x - 0.5x = 12 - 20\\\\-0.25x = -8\\\\0.25x = 8\\\\Divide\ both\ sides\ by\ 0.25\\\\x = 32$

Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

Thus 8 gallons of 50 % antifreeze is used

6 0

3 years ago