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Effectus [21]
3 years ago
8

While testing a new vaccine, a lab technician noticed that the number of bacteria reduced by half every minute. How long does it

take for 3,000 bacteria to reduce to 375?
It takes
minutes for the number of bacteria to reduce from 3,000 to 375.
Mathematics
1 answer:
son4ous [18]3 years ago
5 0
To start, find your equation, n=3000(.5)^t, n being your number of bacteria and t being your time. Now plug in 375 for n and solve for t, 375=3000(.5)^t, .125=.5^t, t=log_{.5} .125=3. This means your answer is 3 minutes. To check it, plug it into your equation. n=3000(.5)^t=3000(.125)=375
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yaroslaw [1]

The function g(x) will be given as g(x) = – ∛(x – 1). Then the correct option is D.

The complete question is attached below.

<h3>What is a transformation of geometry?</h3>

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

Translation does not change the size and shape of the geometry.

The function f(x) is given below.

f(x) = ∛x

Then the function of the g(x) will be

g(x) = – ∛(x – 1)

Then the correct option is D.

More about the transformation of geometry link is given below.

brainly.com/question/22532832

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You earn 15n15n dollars for mowing nn lawns. how much do you earn for mowing one lawn? seven lawns?
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4 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

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