X=length
y=width
Area (rectangle)=length x width
we suggest this system of equations:
y=x/5
xy=9/20
solve this system of equations by substitution method:
x(x/5)=9/20
x²/5=9/20
Least common multiple=20
4x²=9
x²=9/4
x=⁺₋√(9/4)
we have two solutions:
x₁=-3/2 it does not validate
x₂=3/2 ⇒y=x/5=(3/2)/5=3/10
The dimensions of the lake are:
lengh=3/2 miles
width=3/10 miles
to check:
Area=3/2 miles x 3/10 miles=9/20 miles².
width is 1/5 the length of the lake ⇒ 3/10 miles=(3/2) /5 miles
I think the answer is 9-25x
To solve this problem you must apply the proccedure shown below:
1. You have that the time, given in the problem above, is written in decimal form.
2. To express this time in words, you must begin from left to right. First, write the digits before the point (58) and after the points (329) as whole numbers. Then, finish it writting the place name of the last digit, as following:
(Note: The point is expressed as "and").
58.329: Fifty eigth and three hundred twenty nine thousandths.
Therefore, the answer is: Fifty eigth and three hundred twenty nine thousandths.
Answer:
Step-by-step explanation:
