Evaluate quantity the square root of 16 times 3 squared minus the cube root of negative 27 end quantity divided by 2 squared.

Mathematics

2 answers:

MrRissso [65]1 year ago

8 0

Answer:

the perimeter of rectangle is 52cm if two adjacent sides are (2×+3)cm and (×+5)cm

Pepsi [2]1 year ago

5 0

1) The square root of 16 is 4, and 4 times 3 squared so 4 times 9 is 36

2) The cube root of -27 is -3

So butting both step 1) and 2) together, you get the equation: 36 - -3 = 39

And lastly you divided 39 by 2 squared so 4

= 39/4

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3 years ago

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Lilit [14]

Answer:

<h3> Perimeter = 3√5 + 6 + √73 + √58 + 5√2</h3>

Step-by-step explanation:

$AB=\sqrt{(6-0)^2+(5-8)^2}=\sqrt{36+9}=\sqrt{45}=3\sqrt5\\\\BC=|-1-5|=|-6|=6\\\\CD=\sqrt{(-2-6)^2+(-4-(-1))^2}=\sqrt{64+9}=\sqrt{73}\\\\DE=\sqrt{(-5-(-2))^2+(3-(-4))^2}=\sqrt{9+49}=\sqrt{58}\\\\EA=\sqrt{(0-(-5))^2+(8-3)^2}=\sqrt{25+25}=\sqrt{25\cdot2}=5\sqrt2$