Answer: not and identity
Step-by-step explanation:
The wide-area search method employs the use of markers such as knots at regular intervals along the search line.
Given the method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line.
In order to locate, relieve distress, and preserve the life of a person who has been reported missing or is believed to be lost, stranded, or is considered a high-risk missing person, wide area search and rescue refers to activities occurring within large geographic areas. It also refers to the removal of any survivors to a safe location.
Hence, the wide-area search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line
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Step-by-step explanation:
1. making the equation:
shoes = x
shirts = y
175 = x + 3y
x = 4y
2. graph it (I'm using desmos)
the green line is for 175 = x + 3y and the purple one is for x = 4y
3. find the price
x = 4y
175 = 4y + 3y
175 = 7y
y = 175/7 = $25
price of the shirt = $25
x = 4y = 4*25 = $100
price of a pair of shoes = $100
1. 8+5=13
2. 13 x 3 x 10 = 13 x 30 = 390
Using the information above transform the ratio 8:5.
8 x 30 : 5 x 30
If you do this, you'll end up with the ratio:
240 : 150
This means that 240 adults attended whilst 150 children attended.
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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