We are given: Function y=f(x).
First x-intercept of the y=f(x) is 2.
x-intercept is a point on x-axis, where y=0.
Replacing y by 0 and x by 2 in above function, we get
0=f(2)
Second x-intercept of the y=f(x) is 3.
Replacing y by 0 and x by 2 in above function, we get
0=f(3)
We are given another function y=8f(x).
Here only function f(x) is being multiplied with 8.
That is y values of function should be multiply by 8.
Because we have y value equals 0. On multiplying 8 by 0 gives 0 again and it would not effect the values of x's.
Therefore,
x-intercepts of y=8f(x) would remain same, that is 2 and 3.
Answer:
<h2>FALSE</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition
- subtraction
<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>
- <u>
</u> - <u>
</u>
<h2><u>≠R.H.S</u></h2>
therefore
<h3>the equality is false</h3>
The slope-intercept equation is y=mx+b.
The slope formula is 
Our three points are (5,5), (-5,-7) and (0,-1)
Using our slope formula our slope becomes 
Then, if we use one of our points (pick whichever you want, although (0,1) is the easiest) to solve the equation. So,
. When we solve for x and y, we get -1=0+b, or b=-1.
When we plug that back into the equation, we get
.