The required equation is ~
Let's find the slope of given line ~
comparing it with general slope - intercept form of line (y = mx + c) we get, m = -2 (that is slope of the line)
let the slope of the required line be n
And, now since the required line Is perpendicular to the given line. the product of their slopes is -1
that is ~
slope of required line is ~ 1/2
now, let's use the point - slope form of line to find the equation of required (perpendicular) line (using point (0 , 2) ~
that is ~
here, m = slope ~
I hope it helps ~
We know that the area of a rectangle is equal to the width multiplied by the length. So in this case the algebraic expression is (x+5)*(3x+10). You get 3x^2 +10x +15x +50= 3x^2 +25x +50.
540ml with 12% solution
get 12% of 540
540 times 0.12 = 64.8 ml of pure acid
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
No, because 7 x 21 is 147.
