Here’s my answers, for #10 it got cut off but I got m=9/7 and d=11.40
-3x=-18
divide both sides by -3
to get +x
to get x by itself
-3x/-3=-18/-3
cross out -3 and -3, divide by -3
then becomes -1*-1*x=1*x=x
x=-18/-3
answer:
x=6
Answer:
The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857
Step-by-step explanation:
It is said that Actuary Rahul examines a low risk policy
Probability of a low risk policy having a claim = 10% = 0.1
Actuary Toby examines high risk policy
Probability of a high risk policy having a claim = 20% = 0.2
Let the number of policies examined by actuary Rahul before he finds a claim and stop be n
Probability that actuary Rahul examines exactly n policies = 
Probability that Toby examines more than n policies = 
Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = 
probability that both events happen simultaneously = 
The probability that Actuary Rahul examines fewer policies that Actuary Toby =
= 
The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857
Answer:
The volume each of the four barrels of the same size will be at least 47.5 liters.
Step-by-step explanation:
Let the volume of each of the four barrels is v liters.
Now, the amount of water that can be held in the fifth barrel is 10 liters. The total capacity of holding water for the 5 barrels combines is at least 200 liters.
So, from the above-given information, we can write the inequality to determine the volume of each of the four barrels will be
10 + 4v ≥ 200
Solving this we get,
4v ≥ 190
⇒ v ≥ 47.5
Therefore, the volume each of the four barrels of the same size will be at least 47.5 liters. (Answer)
Answer:
9
Step-by-step explanation:
i think plz give brainleast