Question

Two numbers are in the ratio of 3:4. If they sum of the numbers is 63, find the numbers

Answer 1

Answer:

27 and 36

Step-by-step explanation:

Let's call the two numbers x and y.

$3x=4y \\\\x+y=63$

If you subtract y from both sides of the second equation, you can isolate x and substitute it into the first equation:

$x=63-y \\\\3(63-y)=4y\\\\189-3y=4y\\\\189=7y\\\\y=27\\\\x=63-27=36$

Hope this helps!