It depends on how you count them. If you describe them by their dimensions, lowest one first, you can have
1 x 1 x 18
1 x 2 x 9
1 x 3 x 6
2 x 3 x 3
Of course, these dimensions can be put in any order.
Answer:
V = 4/3 pi r^3 for a sphere
Step-by-step explanation:
You can't a circle is a two dimensional object.
The volume of a sphere, which is the three dimensional form of a circle is found by
V = 4/3 pi r^3
Where r is the radius
24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)
8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)
So:
a(n) = a(n-1) + a(n-2)^2
Lets check: 88+24^2= 664
664+88^2= 8408
Answer:Marks below 75%
Step-by-step explanation:
Since the pass marks is 75%,the fail marks should be Marks below 75%
