So hmmm if you notice y = x² - b is really just the parent function x² with a downward shift of "b". And y = - x² + b is really just x² upside-down shifted upwards by "b". so, both parabolas, look like the picture below, and their vertices is at the origin and then they get shifted, one upwards and the other downwards.
So the rhombus lies in their vertices and intersection points.
now, the area of the rhombus is 54, we're taking the green triangle in the picture, which is half of the rhombus, so its area is 27 then, it has a base of "2b", and an altitude of whatever the value of "x" at the intersection happens to be.
so hmmm let's check what's "x" anyway.
8 × 46 = 8 × (40 + 6) = (8 × 40) + (8 × 6) = 320 + 48 = 368
Hope this explains it.
Answer: None the zeroes have a multiplicity of 2.
Step-by-step explanation: i took the test
2000 + 1500g ≤ 15000
1500g ≤ 15000 - 2000
1500g ≤ 13000
g ≤ 13000/1500
g ≤ 8 2/3
Therefore, the crane can safely lift a maximum of 8 2/3 cubic meters of gravel.
Recall that
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
for all <em>θ</em>, and given that cos(<em>θ</em>) < 0, we find that
cos(<em>θ</em>) = -√(1 - sin²(<em>θ</em>)) = -√(1 - (2/5)²) = -√(21)/5
Now,
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = 1/(2/5) = 5/2
and
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>) = (-√(21)/5)/(2/5) = -√(21)/2