Answer:
K = (1/2)r^2(sin(θ) +θ)
Step-by-step explanation:
The area of the triangle to the left is ...
A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)
The area of the sector to the right is ...
A2 = (1/2)r^2θ
so the total area of the blue shaded region is ...
K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ
K = (1/2)r^2(sin(θ) +θ)
Answer:
y = 4 sin(½ x) − 3
Step-by-step explanation:
The function is either sine or cosine:
y = A sin(2π/T x) + C
y = A cos(2π/T x) + C
where A is the amplitude, T is the period, and C is the midline.
The midline is the average of the min and max:
C = (1 + -7) / 2
C = -3
The amplitude is half the difference between the min and max:
A = (1 − -7) / 2
A = 4
The maximum is at x = π, and the minimum is at x = 3π. The difference, 2π, is half the period. So T = 4π.
Plugging in, the options are:
y = 4 sin(½ x) − 3
y = 4 cos(½ x) − 3
Since the maximum is at x = π, this must be a sine wave.
y = 4 sin(½ x) − 3
Answer:
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Step-by-step explanatiicdeon:
Answer:
which of the following angles are congruent to 6? select all that apply.
A. 1
<em><u>B. 3</u></em>
<em><u>C. 2</u></em>
D. 4
