1) find the corresponding y values for when x = 0 and when x = 4,
when x = 0, y = 4
when x = 4, y = 4
the coordinates are (0,4) and (4,4)
2) to calculate the average rate of change, find the slope of the two points:
(0,4) (4,4)
(change in y) 4 - 4 = 0
(change in x) 4 - 0 = 4
0/4 = 0
the average rate of change is 0!
<h3>
Answer:</h3>
Factor 6 from the first two terms.
<h3>
Step-by-step explanation:</h3>
By factoring out "a", you can better see what "h" needs to be.
- y = 6(x^2 +3x) +14 . . . . 6 factored from first 2 terms
- add the square of half the x-coefficient inside parentheses; add the opposite outside: y = 6(x^2 +3x +2.25) +14 -6(2.25)
- rewrite as a square; combine the constants: y = 6(x+1.5)^2 +0.5
1. The x-intercepts are x = 0 and x = 6. You can find these by looking for where the line crosses the x-axis. You can see here that it does so at 0 and 6.
2. The maximum value for this function is looking for the f(x) value at the highest point. In this case, you will see that f(x) at the highest point is 120. This happens at x = 3. Once again, this can be found just by looking for the highest point on the graph.
3. Since that is the absolute highest point, it is also the point where is goes from increasing to decreasing. As a result, we know the increasing interval is x<120 and the decreasing interval is x > 120.
4. Finally, the average rate of change between 3 and 5 is -30. You can find this by determining the amount of change in f(x) and dividing it by the amount of change in x. The basic formula is below.



-30
Answer:
0.8973
Step-by-step explanation:
Relevant data provided in the question as per the question below:
Free throw shooting percentage = 0.906
Free throws = 6
At least = 5
Based on the above information, the probability is
Let us assume the X signifies the number of free throws
So, Then X ≈ Bin (n = 6, p = 0.906)

Now
The Required probability = P(X ≥ 5) = P(X = 5) + P(X = 6)

= 0.8973
Answer:

Step-by-step explanation:
-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:

Where:
is the population after t days.
is the initial population given as 7600
is the rate of growth
is time in days
-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5
-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.
Hence, the exponential growth function will be expressed as:
