Answer:
1.-t₁ = 0,625 s
2.-h(max) = 6,25 f
3.-t = 1,25 s
Step-by-step explanation:
V₀ = 20 f/s
h(t) = - 16*t² + 20*t
h(max) = ??
h´(t) = - 32*t + 20
h(max) will occurs when V = 0 dh/dt = 0 then
- 32*t + 20 = 0
- 32*t = -20
t = 20/32
t₁ = 0,625 s
h(max) = h(0,625) = - 16*(0,625)² + 20*0,625
h(max) = - 6,25 + 12,5
h(max) = 6,25 f
c) The ball will hit the ground
t = 2*t₁
t = 2*0,625
t = 1,25 s
The image is not attached with, but by reading the question it is obvious that the blue region lies inside the larger square and outside the smaller square. That is the region between the two squares is the blue region.
We know the dimensions of both squares, using which we can find the area of both squares. Subtracting the area of smaller square from larger one, we can find the area of blue square and further we can find the said probability.
Area of larger square = 8 x 8 = 64 in²
Area of smaller square = 2 x 2 = 4 in²
Area of blue region = 64 - 4 = 60 in²
The probability that a randomly chosen point lies within the blue region = Area of blue region/Total area available
Therefore, the probability that a point chosen at random is in the blue region = 60/64 = 0.9375
Answer:
1.
centre(h,k)=(-13,9)
radius (r)=6
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x+13)²+(y-9)²=6²
x²+26x+169+y²-18y+81=36
x²+y²+26x-18y+169+81-36=0
x²+y²+26x-18y +214=0
is a required equation of the circle.
2.
centre(h,k)=(1,-1)
radius (r)=11
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-1)²+(y+1)²=11²
x²-2x+1+y²+2y+1=121
x²+y²-2x+2y=121-2
x²+y²-2x+2y=119
is a required equation of the circle.
Answer:
Step-by-step explanation:
Given
Required
Determine the mass of the vehicle
This question will be answered using Newton's second law
Substitute values for Force and Acceleration
Make Mass the subject
---- approximated
<em>Hence, the mass of the vehicle is 1867kg</em>
Answer:
27/20
Step-by-step explanation:
