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3 years ago

10

Demilade piays football for 2 hours, badminton for 3 hours, volleyball for six hours, Nintendo for 1.5 hours and softball for ei

ght hours each week. How many hours per week does he played outdoor

1 answer:

skad [1K]3 years ago

5 0

he plays for 13 hours every week

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What is the solution to y + 7 = -9 A. y = -16 B. y = -2 C. y = 2 D. y = 16

Helen [10]

Answer:

A. y = -16

Step-by-step explanation:

Hello!

What we do to one side of the equation we have to do to the other.

y + 7 = -9

We have to get y by itself so we have to get rid of the seven by doing the opposite of what it says

The opposite of addition is subtraction so we subtract 7 from both sides

y + 7 - 7 = -9 - 7

Solve

y + 0 = -16

Simplify

y = -16

The answer is A. y = -16

Hope this helps!

4 0

3 years ago

What is the value of the y-intercept of the graph of h(x) = 1.2(4.15)^x?

gizmo_the_mogwai [7]

9514 1404 393

Answer:

h(0) = 1.2

Step-by-step explanation:

The y-intercept is h(0). When x=0, the exponential term evaluates to 1, so the y-intercept is the multiplier of the exponential term.

h(0) = 1.2 . . . the y-intercept

7 0

2 years ago

Enter the equation of the circle described below.<br> Center (-3, 0), radius sqrt 5

stealth61 [152]

Hello :
<span> the equation of the circle is (x-a)²+(y-b)² = r²
A(a;b) center r : </span><span>radius
</span>in this exercice : (x+3)²+y²=25

3 0

2 years ago

Read 2 more answers

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

2 years ago

Leta is making strawberry almond salad for a party for every head of lettuce that she uses she adds 5 ounces of almonds and 10 s

Jet001 [13]

15 heads of lettuce and 150 strawberry’s

7 0

3 years ago