1) Graph a straight segment that starts at the point (0, 1000) and (200/13 , 0)

That segment is in the first quadrant and is like a ramp going downward from left to right.

2) a) slope = - 65 is the change in y (the # of miles remaiing) per miles run (change in x). It is negative because when the Vieras have increase the distance run (x), the distance remaining (y) decreases.

b) the y - intercept (1000) representes the distance from the starting point (Philadelphia) fo the destiny (Orlando), i.e. the distance in miles remaining before departing (when x =0).

7 0

3 years ago

|x-3|+4=12 show all steps <br>Please

SOVA2 [1]

Answer:

|x-3|+4 = 12

|x-3| = 12-4

|x-3| = 8

now solve for both positive and negative values

x - 3 = 8 | x - 3 = -8

x = 8 + 3 | x = - 8 + 3

x = 11 | x = -5

solution set : { 11, -5 }

Step-by-step explanation:

3 0

4 years ago

Find the mean median mode and range for the following data 77 60 59 70 89 95

Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

77,60,59,70,89,95

Sort:

59,60,70,77,89,95

To find:

Mean
Median
Mode
Range

Mean:

$\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}$

Sum of all data divides by amount.

$\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}$

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

$\displaystyle \large{\dfrac{x_1+x_2}{2}}$

From 59,60,70,77,89,95, since 70 and 77 are in middle:

$\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}$

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

$\displaystyle \large{x_{max}-x_{min}}$ or highest value - lowest value

Thus:

$\displaystyle \large{95-59 = 36}$

Therefore, range = 36

7 0

2 years ago

Find the value of X so that this quadrilateral is a parallelogram. Then substitute the value of X and using the parallelogram an

Bogdan [553]

Answer:

x = 36

m/A = 132

m/B = 48

m/C = 48

m/D = 132

4 0

4 years ago