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damaskus [11]
3 years ago
9

Divide x4 + 7 by x-3.

Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

x^3   +  3x^2    +   9x    +  27   +   88 / [x - 3]

Step-by-step explanation:

x ^4 + 7 by x - 3 x^3   +  3x^2    +   9x        +  27 x - 3  [  x^4  +   0x^3    +   0x^2    +   0x    +   7   ]. x^3  -    

3x^3 ________________________________ 3x^3   +     0x^2 3x^2  

-     9x^2 ______________ 9x^2      +   0x 9x^2

   -    27x ____________ 27x    +   7 27x  

 -  81 _________ 88 S

Answer:  So the result is :      x^3   +  3x^2    +   9x    +  27   +   88 / [x - 3]

<em><u>Please mark me brainliest</u></em>

<em><u>Hope this helps.</u></em>

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Solve using the elimination method <br>x + 5y = 26 <br>- X+ 7y = 22​
S_A_V [24]

Answer:

x=6\\y=4

Step-by-step explanation:

Elimination method:

x+5y=26

-x+7y=22

Add these equations to eliminate x:

12y=48

Then solve 12y=48 for y:

12y=48

y=48/12

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Write down an original equation:

x+5y=26

Substitute 4 for y in x+5y=26:

x+5(4)=26

x+20=26

x=26-20

x=6

{ x=6 and y=4 }    ⇒ (6,4)

<em />

<em>hope this helps...</em>

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How do you find the equation that is perpendicular to 2x-5y=20, passing through the point (7,-8)?
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