Answer:
Step-by-step explanation:
Let's "complete the square," which will give us the vertex of this vertical, opens-up parabola:
g(x) =x^2+4x+1 can be rewritten as g(x) =x^2+4x + 4 - 4 +1, where that +4 comes from squaring half of the coefficient of x.
Then we have g(x) =x^2+4x + 4 - 4 + 1 => g(x) = (x + 2)^2 - 3.
Comparing this to y = (x - h)^2 + k,
we see that the vertex, (h, k), is located at (-2, -3).
Plot this vertex. Also, plot the y-intercept (0, g(0) ), which is (0, 1).
This information is enough to permit graphing the function roughly.
