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meriva
3 years ago
13

Help me plez and show work

Mathematics
1 answer:
zysi [14]3 years ago
6 0
Sorry i cant answer with the cracks...can't see
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A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
A volleyball player sets the ball in the air, and the height of the ball after t seconds is given in feet by h= -16^2+12t+6. A t
JulsSmile [24]

h=-16²+12t+6

8=-256+12t+6

256-6+8=12t

-258=12t

t=-258/12

t=21.5

7 0
3 years ago
I'm even more confused now... now which is bigger one hundred fifty-eight thousandths or 0.58 plsssss help me!!!!!
hram777 [196]

Answer:

0.58 is larger

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which shape has no parallel sides?<br> rectangle<br> trapezoid<br> square<br> triangle
nadezda [96]

Answer:

Triangle

Step-by-step explanation:

all of them have parallel sides except triangle

5 0
2 years ago
Read 2 more answers
Find the distance between points M (6,16) and Z (-1,14) to the nearest tenth, please help step by step
insens350 [35]
The distance between 2 points P(a, b) and Q(c,d) is given by the formula:

\displaystyle{d= \sqrt{(b-d)^2+(a-c)^2}, 


Apply the formula for the points M(6, 16) and Z(-1, 14):

\displaystyle{d= \sqrt{(16-14)^2+(6-(-1))^2}= \sqrt{2^2+7^2}= \sqrt{4+49}= \sqrt{53}\approx 7.28

which rounded to the nearest tenth is 7.3 (units)

Answer: 7.3 units
3 0
3 years ago
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