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IRISSAK [1]
3 years ago
8

2x=10y+14, 6x-2y=2x+28 how do I solve this problem using algebraic method?

Mathematics
1 answer:
yuradex [85]3 years ago
4 0
PEMDAS- Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction.

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1x-4=2x<br>anwser <br>need the written equation
Debora [2.8K]
1x - 4 = 2x
(minus the 1x from the left to cancel it out and minus it to other side making the 2x a 1x or just x)⤵️

-4 = x

and that is the answer
4 0
3 years ago
A null hypothesis can only be rejected at the 5% significance level if and only if:
uranmaximum [27]
<span>The probability of the outcome's occurrence by "chance" is 5% or less. "Chance" results are those that are within normal variation, which is defined as 2 standard deviations from the mean. Results that are less than 2 standard deviations from the mean are considered not statistically significant, meaning that the null hypothesis should not be rejected. There are some differences the point at which the 5% case occurs, depending on whether the null hypothesis is directed or not.</span>
4 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
MrRa [10]

Answer:

C 0 solutions

Step-by-step explanation:

8x+47 = 8(x+5)

Distribute

8x+47 = 8x+40

Subtract 8x from each side

47 = 40

This is never true so there are no solutions

8 0
3 years ago
Read 2 more answers
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
2,759 divided by 89?
EleoNora [17]

Answer:

31

Step-by-step explanation:

I can't explain any further......

8 0
2 years ago
Read 2 more answers
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