Question

) Tara earns twice as much per hour as Kayte.

Answer 1

Answer:

Austin's hourly wage is $8.

Step-by-step explanation:

We can write this problem as a system of linear equations.

We define T: Tara's hourly wage, A: Austin's hourly wage and K: Kayte's hourly wage.

Then, if Tara earns twice as much per hour as Kayte, we have:

$T=2K$

If Kayte earns $3 more per hour than Austin, we have:

$K=A+3$

And if they earn $41 per hour as a group, we know:

$T+K+A=41$

We can use all equations to replace in the third one, as:

$T+K+A=41\\\\(2K)+K+A=41\\\\3K+A=41\\\\3(A+3)+A=41\\\\3A+9+A=41\\\\4A=41-9=32\\\\A=32/4=8$

Austin's hourly wage is $8.

Answer 2

Answer:

Austin's hourly wage is $8.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

Tara's hourly wage is x.

Kayte's hourly wage is y.

Austin's hourly wage is z.

Tara earns twice as much per hour as Kayte.

This means that $x = 2y$

Kayte earns $3 more per hour than Austin.

This means that $y = z + 3$

As a group, they earn $41 per hour.

This means that $x + y + z = 41$

What is Austin's hourly wage?​

This is z.

$x + y + z = 41$

$y = z + 3$ and $x = 2y$, so $x = 2(z + 3) = 2z + 6$

$x + y + z = 41$

$2z + 6 + z + 3 + z = 41$

$4z + 9 = 41$

$4z = 32$

$z = \frac{32}{4}$

$z = 8$

Austin's hourly wage is $8.