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3 years ago

The two angles are

Mathematics

1 answer:

Natalka [10]3 years ago

6 0

Answer:

The two angles are alternate interior angles

Step-by-step explanation:

Here, we want to state the relationship between the two given angles

From the diagram, we can observe that these two angles are;

They are alternate interior angles

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Need help asap question in picture

Neporo4naja [7]

Answer:

The triangle is a obtuse triangle

Step-by-step explanation:

5 0

3 years ago

charles leaves the marina and sails his boat 10° west of north for 1.5h at 18km/h. he then makes a right turn to a heading of 60

Ymorist [56]

<span>If Charles leaves the marina and sails his boat 10° west of north for 1.5h at 18km/h, then makes a right turn towards 60° east of north for 1.2h at 20km/h, he is 42 km from his starting point.</span>

5 0

3 years ago

[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

3 years ago

Mary will rent a car for the weekend. She can choose one of two plans. The first plan has no initial fee but costs $0.70 per mil

AlexFokin [52]

Mary would have to drive 750 for the plans to be the same.

7 0

3 years ago

Read 2 more answers

If you have 16 cups of sugar , 2 cups of sugar for every batch of cookies , but you have to save 6 cups of sugar for something e

sesenic [268]

The first step we want to take here is to subtract 6 cups of sugar since we'll need it for something else, leaving us with 10 cups of sugar. It takes 2 cups of sugar for every batch of cookies, so you're going to divide 10 by 2. Luckily, 2 is a multiple of 10 so it's a whole number. By dividing, we get 5. So, we can make 5 batches of cookies while still saving 6 cups of sugar for something else.

8 0

3 years ago