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Lady bird [3.3K]
3 years ago
7

Which number gives you an irrational product when you multiple it by 0.2

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

the answer is

\sqrt{5}

as you can see I got it right.

Vinil7 [7]3 years ago
6 0
Is the question complete or is that 0.25?
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Twin brothers,billy and Bobby, can mow their grandparents lawn together in 72 minutes. Billy could mow the lawn by himself in 15
Alla [95]

Answer:

Billy used 28 mins 30 sec to mow the lawn and Bobby used 43 mins 30 sec to now the lawn both within 72 mins

Step-by-step explanation:

let x represent Billy

let x+15 represent Bobby

x + x + 15 = 72

2x = 72 - 15

2x = 57

2x/2 = 57/2

x = 28.5 minutes = 28 minutes 30 seconds

Bobby = x + 15

= 28.5 + 15

= 43.5 minutes= 43 minutes 30 seconds

6 0
3 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
GenaCL600 [577]

Close off the hemisphere S by attaching to it the disk D of radius 3 centered at the origin in the plane z=0. By the divergence theorem, we have

\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV

where R is the interior of the joined surfaces S\cup D.

Compute the divergence of \vec F:

\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2

Compute the integral of the divergence over R. Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}

So the volume integral is

\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5

From this we need to subtract the contribution of

\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S

that is, the integral of \vec F over the disk, oriented downward. Since z=0 in D, we have

\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k

Parameterize D by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

where 0\le u\le 3 and 0\le v\le2\pi. Take the normal vector to be

\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

Then taking the dot product of \vec F with the normal vector gives

\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v

So the contribution of integrating \vec F over D is

\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4

and the value of the integral we want is

(integral of divergence of <em>F</em>) - (integral over <em>D</em>) = integral over <em>S</em>

==>  486π/5 - (-81π/4) = 2349π/20

5 0
3 years ago
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true
aleksley [76]

- I think it's possibly this "The figure must be a square because the diagonals of a square bisect the right angles." but there's also "The figure must be a rhombus because it has exactly 2 pairs of congruent angles." buuut since the first one seems more better i'm assuming then that's probably the right answer.

5 0
4 years ago
PLEASE HELP! The question is in the attachment.
Olin [163]

Answer:

x > 1

Step-by-step explanation:

15 - 1 = 14

The inequality is 15 - 1 < 14, but this is incorrect. 14 can not be less than 14. In order for the left side to be less than 14, the x value (currently representing 1) should be larger than what it currently is to make the statement true.

Therefore, x>1

3 0
3 years ago
Choose the expressions that are perfect cubes
Ludmilka [50]

Answer: the second fifth and sixth one

Step-by-step explanation:

4 0
3 years ago
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