Answer:
A. x=6 B. x=4.5 C. x-35 D. x=13
Step-by-step explanation:
For A and B, divide the numbers you have. For C and D, multiply the numbers you have.
2³-4²
= 8-16
=-8
Hopefully this helps! Good luck! :)
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.
To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5
Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26
We now divide this by the number of data points:
26/10 = 2.6
This is a measure of how much each bag of candy varies from the mean.
Subtract 4 from both sides of the equation.
y=-4-2x+2
add -4 and +2.
the answer is
y=-2x-2
Answer:
second option
G(3 , -4) ; H(8 , 1)
Step-by-step explanation:
For the line GH to be a median, the point G must have the intermediate value at x and at y between points A and B, and the point H must have the intermediate value at x and at y between points A and B
G = (Ax + Bx)/2 , (Ay + By)/2
G = (3 + 3)/2 , (-9 + 1)/2
G = 6/2 , -8/2
G = (3 , -4)
H = (Cx + Bx)/2 , (Cy + By)/2
H = (13 + 3)/2 , (1 + 1)/2
H = 16/2 , 2/2
H = (8 , 1)
This is because for a medium to be the point p has to be right in the middle of the other 2 vertices