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geniusboy [140]
2 years ago
12

You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.

2 lines connect and go up to the right and down to the right. The line that goes up to the right points to Ace, and the line that goes down to the right points to Not an ace. StartFraction 4 Over 52 EndFraction is above the lines, and StartFraction question mark Over 52 EndFraction is below the lines. Write the equation for the expected value. E(V) = 4 52 (a) + b 52 (c) a = b = c =
Mathematics
1 answer:
denis-greek [22]2 years ago
7 0

Answer:

Step-by-step explanation:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

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