M=−8r ^2 +11r−6 T=−7r ^2−9r+14 M+T= Answer is: −15r ^2 +2r+8
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Answer:
His average speed on the second day is 35 miles per hour.
Step-by-step explanation:
Consider the provided information.
On first day, he drove 2 hours longer than he drove on second day.
Let x = Number of hours he drove on second day.
Then x + 2 = Number of hours he drove on first day.
It is given that he drove a total of 18 hours.
Therefore,
He drove 8 hours on second day.
x + 2 = 8+2=10
He drove 10 hours on first day.
Let y = speed driven on second day.
y + 5 = speed driven on first day.
As we know: Distance = speed × time
On first day he covers a distance of:
Distance = 10(y+5)
On second day he covers a distance of:
Distance = 8(y)
Total distance = Day 1 distance + Day 2 distance
Hence, his average speed on the second day is 35 miles per hour.