I keep getting this wrong can y’all help me please
1 answer:
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Answer:
1/2
Step-by-step explanation:
if you look at a unit circle, sin(\pi/6) is so cos of (\pi/6/2) would be \pi/3, and cos of (\pi/3) is 1/2
Answer:
Please check the explanation.
Step-by-step explanation:
- Two lines are parallel if their slopes are equal.
- Two lines are perpendicular if the product of their slope is -1
We also know that the slope-intercept form of the line equation is
where m is the slope and b is the y-intercept
Given the lines
1)
- y = 6х - 3
Comparing with y=mx+b, the slope of y = 6х - 3:
m₁=6
- y = - 1/6x + 7
Comparing with y=mx+b, the slope of y = - 1/6x + 7:
m₂=-1/6
As
m₁ × m₂ = -1
6 × - 1/6 = -1
-1 = -1
Thus, the lines y = 6х - 3 and y = - 1/6x + 7 are perpendicular.
2)
- y = 3x + 2
Comparing with y=mx+b, the slope of y = 3x + 2:
m₁=3
- 2y = 6x - 6
simplifying to write in slope-intercept form
y=3x-3
Comparing with y=mx+b, the slope of y=3x-3:
m₂=3
As the slopes of y = 3x + 2 and 2y = 6x - 6 are equal.
i.e. m₁ = m₂ → 3 = 3
Thus, the lines y = 3x + 2 and 2y = 6x - 6 are paralle.
3)
- 8x - 2y = 3
simplifying to write in slope-intercept form
y = 4x - 3/2
Comparing with y=mx+b, the slope of y = 4x - 3/2:
m₁=4
- x + 4y = - 1
simplifying to write in slope-intercept form
y=-1/4x-1/4
Comparing with y=mx+b, the slope of y=-1/4x-1/4:
m₂=-1/4
As
m₁ × m₂ = -1
4 × - 1/4 = -1
-1 = -1
Thus, the lines 8x - 2y = 3 and x + 4y = - 1 are perpendicular.
4)
- 3x+2y = 5
simplifying to write in slope-intercept form
y = -3/2x + 5/2
Comparing with y=mx+b, the slope of y = -3/2x + 5/2:
m₁=-3/2
- 3y + 2x = - 3
simplifying to write in slope-intercept form
y = -2/3x - 1
Comparing with y=mx+b, the slope of y = -2/3x - 1:
m₂=-2/3
As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.
5)
- y - 5 = 6x
simplifying to write in slope-intercept form
y=6x+5
Comparing with y=mx+b, the slope of y=6x+5:
m₁=6
- y - 6x = - 1
simplifying to write in slope-intercept form
y=6x-1
Comparing with y=mx+b, the slope of y=6x-1:
m₂=6
As the slopes of y - 5 = 6x and y - 6x = -1 are equal.
i.e. m₁ = m₂ → 6 = 6
Thus, the lines y - 5 = 6x and y - 6x = -1 are paralle.
6)
- y = 3х + 9
Comparing with y=mx+b, the slope of y = 3х + 9:
m₁=3
- y = -1/3x - 4
Comparing with y=mx+b, the slope of y = 1/3x - 4:
m₂=1/3
As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.