\left[x \right] = \left[ 0\right][x]=[0]
Answer:
no solution
Step-by-step explanation:
Given
3(x - 3) = 3x , that is
3x - 9 = 3x ( add 9 to both sides )
3x = 3x + 9 ( subtract 3x from both sides )
0 = 9 ← not possible
This indicates the equation has no solution
<u>Answer:</u>
The range of the function y = 2cos x is -2 <y < 2 .
<u>Step-by-step explanation:</u>
We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,
since ,
cos (x + 2π) = cos x
So, the range of the function y = 2cos x is -2 <y < 2 .
There are 60 girls 20 boys in this equation.
2(5.9) is 11.8
Hopefully i is right I did this in my head.