Question

The shadow of a 60 foot pole is a 100 feet long. What is the angle of evaluation from the end of the shadow to the top of the pole?

Answer 1

Answer:

The angle is approximately $31^{o}$.

Step-by-step explanation:

The description i the given question can be represented with the sides of a right angled triangle.

Applying the appropriate trigonometric function, we have;

Tan θ = $\frac{opposite}{adjacent}$

In the question, opposite side = 60 feet, and adjacent side = 100 feet.

Tan θ = $\frac{60}{100}$

         = 0.6

θ = $Tan^{-1}$ 0.6

  = $30.964^{o}$

θ = $31^{o}$

The angle of elevation from the end of the shadow to the top of the pole is $31^{o}$.