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3 years ago

Select the correct answer.

Mathematics

1 answer:

Katena32 [7]3 years ago

3 0

I don’t know I can’t see you right away

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With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en

mrs_skeptik [129]

Answer:

0.9167 = 91.67% probability that the entire batch will be accepted

Step-by-step explanation:

The CDs are chosen without replacement, which means that the hypergeometric distribution is used.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

2100 write-rewrite CDs, and 60 are defective.

This means, respectively, that $N = 2100, k = 60$

3 of these CDs are randomly selected for testing

This means that $n = 3$

What is the probability that the entire batch will be accepted?

Probability of none defective, so P(X = 0).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,2100,3,60) = \frac{C_{60,0}*C_{2040,3}}{C_{2100,3}} = 0.9167$

0.9167 = 91.67% probability that the entire batch will be accepted

5 0

3 years ago

What two fractions can I multiply to make 2/3?

chubhunter [2.5K]

Answer:

2/3*3/3

Step-by-step explanation:

I mean its just doing 2/3 * 1 which i mean, 3/3 is still a fraction so i did it (TBH cant think of anything else

3 0

2 years ago

Read 2 more answers

If M is the set of all square of integers that are less than 100 and N is the set of all positive odd numbers that are under 15,

ollegr [7]

A set is simply the group of numbers.

The set of M and N are: $M = \{1,4,9,16,25,36,49,64,81\}$ and $N= \{1,3,5,7,9,11,13\}$ .
The set of M n N is: $M\ n\ N = \{1,9\}$ .
The set of M u N is: $M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

(a) The set of M and N

Given that:

M = squares of integers less than 100

N = Positive odd numbers less than 15

So, we have:

$M = \{1,4,9,16,25,36,49,64,81\}$

$N= \{1,3,5,7,9,11,13\}$

(b) M n N and M u N

M n N is the set of common elements between sets M and N.

So, we have:

$M\ n\ N = \{1,9\}$

M u N is the set of all elements in sets M and N.

So, we have:

$M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$