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4 years ago

^ this week, The sparkling water was 4 for $5 , the regular was $1.69

Mathematics

1 answer:

S_A_V [24]4 years ago

4 0

This week you paid $1.25 each because they were on sale for four for $5.

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Mrs. Valdez wanted to determine the number of people, p, she could safely take in her car to the fun run. She determined that p

dolphi86 [110]

Answer:

for the first question b,

it doesn't make sense for choice a to have -2 people in the car. You can't have a negative amount of people. For choice choice c, you can't have half a person, and for choice d, Ms. Valdez can only have under 5 people, not five people exactly.

for the second question I need to see the whole inequality, generally there is a variable, and all i see is <-1, which is invalid.

hope this helps, if it does like it pls!!

Step-by-step explanation:

5 0

3 years ago

Answer this algebraic expression. 58 less than j

Crazy boy [7]

Answer:

$j - 58$

That is the meaning of the algebraic expression

4 0

3 years ago

PLEASE HELPP!!!! I’m sorry if you can’t read it well.

Gnom [1K]

Given that y=kx
After substituting any of the given values, we will get constant k as -0.75 or -3/4
So the answer is B. -3/4

3 0

3 years ago

Mark has a six-sided number cube. Each side is numbered from 1 to 6. What is the probability, expressed as a ratio, that Mark wi

emmasim [6.3K]

3 is on the cube only 1 time so 1 out of 6 or 1/6

3 0

3 years ago

Read 2 more answers

A right cylinder is inscribed in a sphere of radius r. How do you find the largest possible volume of such a cylinder?

satela [25.4K]

Answer:

Step-by-step explanation:

Suppose Radius of sphere is R and cylinder inscribed inside the sphere is r with height h

using Pythagoras theorem in shown triangle

$R^2=r^2+(\frac{h}{2})^2$

$r^2=R^2-(\frac{h}{2})^2$

Volume of cylinder is

$V=\pi \times r^2\times h$

$V=\pi \times (R^2-(\frac{h}{2})^2)\times h$

$V=\pi (R^2\cdot h-\frac{h^3}{4})$

differentiate V w.r.t to h we get

$\frac{\mathrm{d} V}{\mathrm{d} h}=\pi (R^2-\frac{3h^2}{4})$

Putting $\frac{\mathrm{d} V}{\mathrm{d} h}$ to get maxima/minima

$R^2=\frac{3h^2}{4}$

$h=\frac{2R}{\sqrt{3}}$

therefore radius r is given by

$r=\sqrt{\frac{2R}{3}}$

therefore volume is given by

$V=\frac{4}{3\sqrt{3}}\pi R^3$

5 0

3 years ago