Point P lies on the line with the equation y-4=3(x-2). If the x-coordinate of P is 4, what is the y-coordinate of P
1 answer:
Let's start by tidying up that equation and put it into slope-intercept form (y = mx + b); from there, we can plug in coordinates.
Let's use the distributive property on the right side:
Now add 4 to both sides
Which simplifies to:
Since that's the equation of our line, now we can plug in coordinates and see what it churns out.
We know that the x-coordinate of P = 4 so let's substitute 4 in for x and calculate the y-coordinate:
So the y-coordinate for point P = 10
Let's use the distributive property on the right side:
Now add 4 to both sides
Which simplifies to:
Since that's the equation of our line, now we can plug in coordinates and see what it churns out.
We know that the x-coordinate of P = 4 so let's substitute 4 in for x and calculate the y-coordinate:
So the y-coordinate for point P = 10
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Answer:
Period ⇒ 40
Amplitude ⇒ 12
Mid-line ⇒ 32
Step-by-step explanation:
The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40
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The amplitude can be found by using the following:
Our maximum is 44 and our minimum is 20.
The amplitude is 12
The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)
44 - 12 = 32
20 + 12 = 32
Therefore our mid-line is y = 32
~Hope this helps!~