The radius of a circle is 9in. Find it’s circumference in terms of

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

3 0

${ \bf{ \underbrace{Given :}}}$

Radius of the circle " $r$ " = 9 in.

${ \bf{ \underbrace{To\:find:}}}$

The circumference of the circle.

${ \bf{ \underbrace{Solution :}}}$

$\sf\orange{The\:circumference \:of\:the\:circle\:is\:56.52\:in.}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

We know that,

$\sf\purple{Circumference\:of\:a\:circle \:=\:2πr }$

$= 2 \times 3.14 \times 9 \: in \\ \\ = 56.52 \: in$

Therefore, the circumference of the circle is 56.52 in.

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}$

You might be interested in

Someone please help me? I don't know how to solve these :/

forsale [732]

$2x^2 - x - 6 = 0$

$(2x - 3) (x + 2) = 0$

$2x - 3 = 0$

$2x = 3$

$x = \frac{3}{2}$

$x + 2 = 0$

$x = -2$

$x = \frac{3}{2} , 2$

7 0

2 years ago

Read 2 more answers

Find what the question asks. 200 points. Will mark brainleist

kotegsom [21]

Note:
The area of a circle with radius r is πr².
An entire circle has a central angle of 360°.

For the sector with radius = (3+4) = 7cm and a central angle of 120°, the area is
$A_{1}= \frac{120}{360}*(49 \pi ) = \frac{49}{3} \pi \, cm^{2}$

For the sector with radius = 3 cm and a central angle of 120°. the area is
$A_{2}= \frac{120}{360} *(9 \pi ) = 3 \pi \, cm^{2}$

The area of the shaded sector (see the figure) is
$A=A_{1}-A_{2} = ( \frac{49}{3} -3) \pi = \frac{40}{3} \pi \, cm^{2}$

Answer: $\frac{40}{3} \pi \, cm^{2}$