Answer:
(a) capacity=3.05hours
(b) utilisation percentage= 0.90 or 90%
(c) Average inventory=1.22
(d)Batch size of D700 is approximately equal to 7
Explanation:
(a)To calculate Capacity
=( Batch size) /(set up time + processing time)
= 12/ (32+17×12) = 12/236 minutes = (12/236) ×60 hours =
3.05 hours
(b)Capacity for assembly: = 113/6 = 18.8/minute = 60/18.8 = 3.19/hour as assembly takes 113 minutes per housing per worker and 6 workers are working at the moment Assembly time for batch of 12 housings = 12/3.19 hr = 3.77 hr CNC time for batch = 32+(17×12 )= 236 minutes = 3.93 hr Utilization of CNC: = (17*12)/60/3.766 = 0.902815 = 0
O.90 or 90%
(c)Average inventory = 1/2 ×batch size × (1-(capacity for assembly × 1/4))
= 1/2×12*(1-(3.186/4) = 1.22(Approximately)
(d)Total demand of all the housings = 0.4+0.5+0.6+0.7+0.8 = 3/hour
Setup time per housing = 32/60 hr = 0.53 hr
Setup time for 5 housings will be = 5×0.53 = 2.67 hr
The Processing time = 17/60 hr = 0.2833 hr
Total batch size = (2.67×3)/(1-3×0.2833) = 53.36
Batch size of D700 = 53.36*(0.4/3) = 7.11 = 7(approximately)