The time intervals when the riders could see Niagara falls are; 0.834 < t < 1.416 and (3.084, 3.666)
<h3>How to interpret Cycle Graphs?</h3>
From the diagram attached, we can say that;
Period = 2π/k
where;
k = 2π/2.25
k = 8π/9
Thus;
h(t) = -(48/2) cos (8π/9)t + ((48/2) + 0.5)
h(t) = -24cos (8π/9)t + 24.5
Riders can see Niagara falls if they are higher than 41 meters above the ground. Thus;
41 = -24cos (8π/9)t + 24.5
41 - 24.5 = -24cos (8π/9)t
16.5 = -24cos (8π/9)t
-0.6875 = cos (8π/9)t
cos⁻¹0.6875 = (8π/9)t
t = 0.834 min
Thus, time interval is between;
0.834 < t < (2.25 - 0.834)
⇒ 0.834 < t < 1.416 and
(2.25 + 0.834) < t < (2.25 + 1.416)
⇒ (3.084, 3.666)
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Answer:
D. 14 Please mark as brainliest!
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
The right answer for the question that is being asked and shown above is that: "The southern California study with a margin of error of 4.9%." the study has the smallest margin of error for a 98% confidence interval is that The southern California study with a margin of error of 4.9%.<span>
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<h2><u>Solution</u> :-</h2>
Given : Radius of cylinder = 8 m
Height = 4 m
Volume of cylinder = πr²h cu. units
= 22/7 × 8 × 8 × 4 m³
= 804.57 m³ (approx.)
Curved surface area = 2πrh sq. units
= 2 × 22/7 × 8 × 4 m²
= 201.14 m² (approx.)
Total surface area = 2πr(r + h) sq. units
= 2 × 22/7 × 8 (8 + 4) m²
= 2 × 22/7 × 8 × 12 m²
= 603.43 (approx.)
