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2 years ago

Rewrite the decimal in the sentence below as a percentage.

Mathematics

1 answer:

serious [3.7K]2 years ago

6 0

Answer:

0.0066%

Step-by-step explanation:

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Please help I’ll give you points and mark you brainliest

elixir [45]

ANSWER:

i think it’s c

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2 years ago

Help please !! thank youu

VLD [36.1K]

Answer:

d = √91 ft = about 9.53 ft

Step-by-step explanation:

use pythagorean theorem which is a²+b²=c²

(the hypotnuse which is opposite side of the right angle is always going to be C in the pythagorean theorem)

a = 3 b = ? c = 10

(3)² + b² = (10)²

9 + b² = 100

subtract 9 from both sides

b² = 91

take the square root of both sides

b = ±√91

so the side d = √91 ft = about 9.53 ft

3 0

2 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

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2 years ago

BRAINLIEST PLEASE HELP

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3 years ago

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The answer is x=14% I just took the quiz so.

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3 years ago

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