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Tatiana [17]
3 years ago
9

Can anyone help please

Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0
Hey I cane use app here no one help u wait a Lott but I use app name guthmath it’s red in colour use code P9EJ5H to get free answer a youtber said that I said no way lies but I had math test me used it and got perfecto
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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
2.5n=45;n=18<br> Determine if the given value is the solution of the equation
Maksim231197 [3]
Well,

2.5(18) = 45
45 = 45

It's as simple as that.  n=18 is the solution to the problem.
5 0
3 years ago
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Which system of equations is represented by the graph?
valentina_108 [34]
I believe the answer is D
4 0
3 years ago
An integer is chosen at random from 1 to 50 inclusive. Find the probability that the chosen integer is divisible by 3. A- 3/50 B
11111nata11111 [884]
First, we need to know how many things between 1 and 50 are divisible by 3, this would be 16. Then we would divide this by the total number of integers, 16/50=8/25. This means your answer is C.
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3 years ago
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Is 7/20 and 0.07 equivalent numbers
IceJOKER [234]
\frac{7}{20}=0.35 \\ &#10; \\  \frac{7}{100}=0.07 \\ &#10; \\ Solution: No \ they \ are \ not \ equivalent \ fractions \\
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4 years ago
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