3grams as a percentage of 20 grams
1 answer:
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Answer:
x = 5
Step-by-step explanation:
Δ EAB and Δ EDC are similar by the AA postulate , so the ratio of corresponding sides are in proportion , that is
=
, substitute values
=
( cross- multiply )
10(x + 3) = 4(2x + 10 ) ← distribute parenthesis on both sides
10x + 30 = 8x + 40 ( subtract 8x from both sides )
2x + 30 = 40 ( subtract 30 from both sides )
2x = 10 ( divide both sides by 2 )
x = 5
Following the table and knowing that the total number of students interviewed were 158 ( we can see this by looking adding either the total number of upperclassment or adding the total number of people with jobs or no jobs, this value is at the bottom right of the table in the figure attached).
Recall that:
In the figure provided each of these terms is highlighted in a different color. To convert these values to their matching probabilities we have to divide each by the total number of students, this is due to the fact that the probability is the number of favorable cases (in this case a group matching the qualities we seek) divided by the total amount of cases ( that is the total number of people interviewed). In the figure the answer is provided. For the intersection of the two events we're looking for people that is both an undercalssman and also has a job.
Recall that:
In the figure provided each of these terms is highlighted in a different color. To convert these values to their matching probabilities we have to divide each by the total number of students, this is due to the fact that the probability is the number of favorable cases (in this case a group matching the qualities we seek) divided by the total amount of cases ( that is the total number of people interviewed). In the figure the answer is provided. For the intersection of the two events we're looking for people that is both an undercalssman and also has a job.