Answer:
Answer is A
Step-by-step explanation:
(14x^4y^6)/(7x^8y^2)
because everything is one term, you can split into three terms
14/7, x^4 / x^8 , and y^6/y^2
multiplying these three terms will get us the starting term
14/7 = 2
x^4 / x^8
with division of exponents, you subtract the smaller exponent (4), from the big exponent (8), and leave it on the same side (bottom) as the big exponent
1/x^4
same thing with our y's
y^6/y^2
this time, the term stays on the top
y^4
take the simplified terms and multiply them together
(2) * (1/x^4) * (y^4) =
A: (2y^4) / (x^4)
Answer: dimond
Step-by-step explanation:
Answer:
1 out of 2
Step-by-step explanation:
Sorry if I’m wrong
Katia and Thomasina play a computer game and record these scores. Katia: 8, 6, -4, -7, 2, 0, 3 Thomasina: -11, 0, 8, 7, 5, -7, 1
suter [353]
Answer:
Step-by-step explanation:
there is no factorization of y^2 -2y +35 in real numbers
Thomasina correctly determined two factors of 35 that differ by 2, but that is not what is needed here. For this problem, she needs two factors of 35 that have a sum of 2.* (There aren't any real-number factors that meet that condition.)
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The factorization in complex numbers would be ...
= (y -1 -i√34)(y -1 +i√34)
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* Technically, she needs two factors of 35 with a sum of -2. Both factors would have to be negative.
