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Jobisdone [24]
3 years ago
13

The coordinates of the vertices of a rectangle are (–2, 3), (4, 3), (4, –4), and (–2, –4). What are the dimensions of the rectan

gle?
Mathematics
2 answers:
Ede4ka [16]3 years ago
8 0
The perimeter of the rectangle is 26 units. You know this because you have one horizontal side of the rectangle going between (-2,3) and (4,3) and another horizontal side including (4,-4) and (-2,-4). You know these are horizontal lines because they pass through the same y coordinates. To find how long these sides are, you simply find the difference between the x coordinates of these points, which is 6 for both sides, because it is a rectangle. Do the same for the vertical lines of the rectangle, and this time take the difference of the y coordinates because the x coordinates stay the same. In this case, the vertical sides of this rectangle are 7 units long. Add up all four sides: 6+6+7+7=26
Paladinen [302]3 years ago
7 0
Find distance of side = (y₂- y₁) / (x₂- x₁)
 
you can get length and width  
then area = length * width
perimeter = 2 * (length + width) 
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Alex17521 [72]

A. subtract the bottom equation from the top equation

Step-by-step explanation:

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation. So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation.

// have a great day //

3 0
3 years ago
Suppose that the functions s and t are defined for all real numbers x as follows.
jeka94

Answer:

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

Step-by-step explanation:

Given functions are:

s(x)= x+6\\t(x)= 4x^2

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2

Also we have to find

(s-t)(x) => we have to subtract function t from function s

(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

(s+t)(x) = s(x)+t(x)\\= x+6+4x^2

Putting x = -3

= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39

Hence,

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

8 0
3 years ago
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