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slavikrds [6]
3 years ago
11

I need help im stuck

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

4712.4

Step-by-step explanation:

I got the same question a few days ago.

The volume is πr^2 * h / 3

r = 15

h =  20

225π * 20 / 3

1500π

It's 4712.38898

Round to 4712.4

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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
ser-zykov [4K]

Answer:

f(x) = x^3 - 2x^2 - x + 2

Step-by-step explanation:

since the zeroes are 1,-1, and 2. we can write the function like

f(x) = (x-1)(x+1)(x-2)

f(x) = (x^2-1)(x-2)

f(x) = x^3 -2x^2 -x +2

and it is true that f(0)=2

4 0
3 years ago
Fill in the blank. I NEED AN ANSWER FASTTT
Yuri [45]

Answer:

It is =

Step-by-step explanation:

Because (6 x 1 = 6 ) + 1  x 1/100 = 6.1  

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2 years ago
Is the product of two integers positive, negative, or zero? How can you tell?
marishachu [46]

Answer:

When you multiply a negative number by a positive number then the product is always negative. When you multiply two negative numbers or two positive numbers then the product is always positive. 3 times 4 equals 12. Since there is one positive and one negative number, the product is negative 12.

Step-by-step explanation:

3 0
3 years ago
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

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