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jarptica [38.1K]
3 years ago
13

Experts/ace plz help me plzzzz

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0
So, the line is going to the <em>right. </em>This is a positive association. If it was going to the left, it would be a negative association. 

It's not super strong, so I would say:

"weak positive association" or "B". 

I hope this helps!
~kaikers 
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A number to the 9th power divided by the same number to the 6th power equals 64. What is the number?
Vika [28.1K]
Use an equation:
x^9/x^6=64
x^(9-6)=64
x^3=64
x=4

note that x^9 means "x to the power of 9", same with other ones

the number is 4.
5 0
3 years ago
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
2 years ago
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Answer:

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3.57%

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6 0
2 years ago
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