D. (7,0)
The original coordinates were (0,7)y and (1,5)x then I rotated it 90 degrees and the coordinates were (7,0)y and (5,1)x
Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
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To find:
The 
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Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]
In triangle AOB,
Therefore, the measure of angle AOB is 120 degrees.
You gave me numbers but forgot the question. Without a question there is no answer.
Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106
In the first table, y = 4x. So y is proportional to x.
In the second table, y is not proportional to x.
In the third table, 2y = 3x. So, y is proportional to x.
