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Alona [7]
3 years ago
13

Correct answers only please!

Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

62.7°

Step-by-step explanation:

9 = Hypotenuse

8 = Opposite

In this question we have to use some trigonometry to work out angle EFG. The first thing we need to identify is will formula will we use out of the following:

Sin⁻¹ = Opposite ÷ Hypotenuse

Tan⁻¹ = Opposite ÷ Adjacent

Cos⁻¹ = Adjacent ÷ Hypotenuse

We know which formula to use because the length won't be in the triangle for example we will be using the Sin triangle because we don't have an adjacent. If we don't have an adjacent then the other formula's won't work.

Now we substitute in the values

Sin⁻¹ = Opposite ÷ Hypotenuse

Sin⁻¹ = 8 ÷ 9

The value of angle EFG is 62.73395555

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Two sides of a triangle have lengths 6 cm and 6cm describe the possible lengths of the third side
Rashid [163]

Answer:

0 < x < 12

Step-by-step explanation:

Since it's given that side a and side b both have a length of 6, side c has to be  0 < x < 12.

6 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
the minute hand of a clock is 5 inches long. what is the area of the circle, in square inches, created in a hand sweep in an hou
ira [324]
Solve the area of the whole circle since in an hour, the minute hand covers the whole clock
assuming that the minute hand reaches all the way out to the edge of the clock


the minute hand is the radius
area=pi times r^2
r=5
5^2=25
area=pi times 25
area=25pi

aprox pi=3.14
25 times 2.14=78.5

area=78.5 in^2
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How high did Abby climb above their original starting<br> position?
PIT_PIT [208]
Idk what are the possible answers
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Ghella [55]

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Step-by-step explanation:

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