The sides of the base of a right square pyramid are 4 m in length , and its slant height is 8 m. If the lengths of the sides of
the base and the slant height are each multiplied by 4, by what factor is the surface area multiplied?
2 answers:
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<h2>Hello!</h2>
The answer is:
The polynomial that can be simplified to a difference of squares is the second polynomial:
To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).
So,
Discarding, we have:
The quadratic terms of the given polynomials are:
We have that the coefficients of the quadratic terms that can be obtained by squaring are:
The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.
So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.
Therefore, we need to work with the second and the third polynomial.
For the second polynomial, we have:
So, the second polynomial can be simplified to a difference of squares.
For the third polynomial, we have:
So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.
Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:
Answer:
96 inch²
Step-by-step explanation:
there are 2 shapes,
1. a square
2. a triangle
lets find the area of the square first,
<u>AREA = SIDE × SIDE</u>
= 8 × 8
= 64 inch²
now, area of triangle ,
so, total area is :
area of square + area of triangle
= 64 + 32
= 96 inch²